The Street Craps, sometimes called Shooting Dice or Ghetto Craps is similar to casino craps but is played without a craps table. The name comes from the way that the game was played in the late 1900’s; on city streets and sidewalks.
A pair of dice is used in the game and the players make wagers on the outcome of rolling the dice. In street craps wagers are made against money that players put up against each other.
Understanding Dice Odds. Last time I discussed the basics of playing craps. In order to play the game youobviously need dice. You also need an understanding of the dice and the odds andprobabilities of rolling the numbers. Recall that the number 7 is the most frequent and probable number to appear when the dice are rolled so your odds of landing it are fairly nice. The odds of actually rolling a 7 are 6 in 36 or 5:1. The house pays out 4:1 on a winning bet, which brings up an outrageous house edge of 16.67%. This is the absolute worst bet you can make in craps. This is actually one of the worst bets a.
- A gambling game played with two dice in which a first throw of 7 or 11 wins, a first throw of 2, 3, or 12 loses the bet, and a first throw of any other number (a point) must be repeated to win before a 7 is thrown, which loses both the bet and the dice.
- The any seven craps bet, also known as big red, is perhaps the most popular and well known wager in the game of craps. Basically all you are doing is betting that the shooter will roll a 7 on the next roll.
- With a minimum of 2 rolls; a point number and then a 7 'craps' when you must pass the dice to the next shooter the odds of rolling a 7 are100% 0 2.
Street Craps Rules
- Players must first identify the player who will be shooting dice – the shooter. The shooter will then need to make a bet followed by the rest of the group in the clockwise direction. Each player can cover a portion of or all of the shooter’s bet. Betting continues until the shooter’s wager is matched.
- The come out roll comes next. This is the game’s first roll and it could end the game if it is a 7, 11, 2, 3 or 12. The shooter and any other player who bet in favor of the shooter win the game if a 7 or 11 is rolled. If a 2, 3 or 12 come up when the dice are rolled the shooter and other players who bet for him lose.
- A Point number, which is a number other than those mentioned above, must be set up. So if the come out roll is not any of those numbers listed above that number will be designated as the point number.
- The roll is next and the goal is for the shooter to roll the number identified as the point before he rolls a 7. The 7 is referred to an “Out 7” and once the shooter gets this before rolling the point he loses the game.
- Rolling dice proceeds until a 7 or the Point is rolled. The shooter loses if the 7 comes up and wins if the Point is rolled. If other numbers are rolled the shooter continues rolling the dice. The round ends only after a 7 or the point is rolled.
It is important that you remember that all bets should be made before the come out roll and you will only win what you bet. As you can see the street craps rules are very similar to rules of casino craps.
Street Craps vs Casino Craps
Rules of street craps vary from casino craps in several ways. The first obvious variation is the absence of a banker. In the street version there is no specific person to handle the money, monitor the bets and pay the winners.
Another difference is that there is no craps table when playing the more informal street craps. This is a disadvantage because it then becomes more difficult to place complicated bets. Due to this street craps usually will only have two betting options – Pass and Don’t Pass. This is limited especially when compared to the numerous options available in casino craps.
A final and very important difference between casino craps and street craps is that the latter is generally illegal. Players must keep their play secret and if they are caught they will face stiff fines.
With this in mind you can decide if you want to play the rolling dice game live and face possible problems with the authorities or you can play the casino version in an offline casino or online.
Category craps information | Tags: , street craps
Warning: Simulations are showing this scheme to be extremely volatile, wiping out the bankroll very quickly due to the extreme size of the first bet. However, it has also shown a large number of really big wins.
I am messing with a scheme where I don't have a PL or DP bet at all.
I wait for a point to be set, and then place a huge bet Across all six numbers.
This bet can be Place bets, Buy Bets, or Puts w/odds, whatever provides best advantage at that table.
When any number hits, take them all down. (If you did Puts, you would have to leave the base, but that would only be $5 or $10, and it would still be in play, so not too bad.)
Wait for the next come out roll and point to be set, and then do the same thing.
Lots of down time with this system, although once you get up, you could turn it into a Regression system instead, where once the first big hit occurs, you take all the bets down to minimum place bets.
Playing this system, only one thing matters.
How often does a shooter roll a 7 right after they set the point?
Note: any junk numbers (2,3,11,12) don't count as a roll, so a roll sequence consisting of:
point 6 set, 2,2,3,7 counts as a 7 out following the point set.
Lots of simulation rolls using WinCraps show my break even point to be right around 4 bets paid for each first roll 7 out.
Here is my question. As I recall all the times I have spent at the craps tables, it does not seem to me that 1 out of every 4 times a point is set, that the shooter rolls a 7 right away. Oh sure, we have all seen it, and I know I have done it more than I care to admit, but 1 out of every 4 points that are set?
I would be interested in what all of your perceptions are. To your best recollection, based on the play you have seen at the tables, how often do you think a 7 is rolled right after the point is set?
one time in six, so you've had some bad luck
the same as if the past was unknown
one time in six, so you've had some bad luck
I don't think it is bad luck, as it happens every time. The longest the scheme has worked is 250 hours (70 rolls/hr), but it always ends with the ratio of wins to 7 outs slightly less than 4 to 1
You are correct, a 7 rolls, 1 out of every 6 times, but I don't think that is the right number for me to expect though.
Since 2,3,11,or 12 don't resolve the bet in my favor, don't I need to discount those rolls.
The times I get a sequence of 6,2,7 for my scheme counts the same as if it were 6,7.
6 ways to make 4/10
8 ways to make 5/9
10 ways to make 6/8
so 24 ways for me to win big bet
6 ways to lose big bet
6 ways the bet is unresolved.
I think this means I have a 66.7% chance of winning the bet, right? (24/36)
And there is a 16.7% chance that the house will get another crack at my bet.
The unresolved bets mean my money is now at risk for another roll of the dice. So my 66.7% chance of a win is going to be reduced, but how do I calculate by how much?
the same as if the past was unknown
one time in six, so you've had some bad luck
I don't think it is bad luck, as it happens every time. The longest the scheme has worked is 250 hours (70 rolls/hr), but it always ends with the ratio of wins to 7 outs slightly less than 4 to 1
You are correct, a 7 rolls, 1 out of every 6 times, but I don't think that is the right number for me to expect though.
Since 2,3,11,or 12 don't resolve the bet in my favor, don't I need to discount those rolls.
The times I get a sequence of 6,2,7 for my scheme counts the same as if it were 6,7.
6 ways to make 4/10
8 ways to make 5/9
10 ways to make 6/8
so 24 ways for me to win big bet
6 ways to lose big bet
6 ways the bet is unresolved.
I think this means I have a 66.7% chance of winning the bet, right? (24/36)
And there is a 16.7% chance that the house will get another crack at my bet.
The unresolved bets mean my money is now at risk for another roll of the dice. So my 66.7% chance of a win is going to be reduced, but how do I calculate by how much?
On $32 across, your expected loss is $.333333 per every roll that you have the bet up. Just because you have a 66.7% change of winning the bet, the losses of throwing a seven completely wipes you out.
6 ways to make 4/10 - win 9/5 units
8 ways to make 5/9 - win 7/5 units
10 ways to make 6/8 - win 7/6 units.
6 ways to make 7 - lose 6.4 units.
(6 * 9/5 + 8 * 7/5 + 10 * 7 / 6 - 6 * 6.4)/36 = -.066667 units. If a unit is $20 dollars, you would be betting $132 across with an expected loss on every roll of $1.333.
You are at risk for this much each time that the dice is rolled and the dice has no memory.
How often does a shooter roll a 7 right after they set the point?
Note: any junk numbers (2,3,11,12) don't count as a roll, so a roll sequence consisting of:
point 6 set, 2,2,3,7 counts as a 7 out following the point set.
Let A be the event of rolling a 2,3,11,or 12. Then p(A) = 6/36 = 1/6.
Let B be the event of rolling a 7. Then p(B) = 1/6.
Rolling 7 In Craps Odds
What you want is some number of A's followed by a B. That is, you wantsum(n = 0 to infinity) p(A)^n*p(B) =
(1/6)^0*(1/6) + (1/6)^1*(1/6) + (1/6)^2*(1/6) + ... = 1/5 = 20%.
This is a geometric series, so the sum is trivial.
That is, 20% of the time you will roll 7 before hitting a number other than 2,3,11 or 12. This is not the intuitively expected number of 1/6. It is a bit more frequent.
As I recall all the times I have spent at the craps tables, it does not seem to me that 1 out of every 4 times a point is set, that the shooter rolls a 7 right away.
1/5 is more often than 1/6, but it is not 1/4.
It's early, your math mileage may vary,
--Dorothy
I played $320 across on the Wizard's craps game and got 7 on the first roll three times in a row.
Aha! Absolute proof that placing bets on the numbers increases the likelihood of a seven being rolled! Now, I know not to do that. Thanks!
How often does a shooter roll a 7 right after they set the point?
Note: any junk numbers (2,3,11,12) don't count as a roll, so a roll sequence consisting of:
point 6 set, 2,2,3,7 counts as a 7 out following the point set.
Odds Of 7 In Craps
Let A be the event of rolling a 2,3,11,or 12. Then p(A) = 6/36 = 1/6.
Let B be the event of rolling a 7. Then p(B) = 1/6.
What you want is some number of A's followed by a B. That is, you want
sum(n = 0 to infinity) p(A)^n*p(B) =
(1/6)^0*(1/6) + (1/6)^1*(1/6) + (1/6)^2*(1/6) + ... = 1/5 = 20%.
This is a geometric series, so the sum is trivial.
That is, 20% of the time you will roll 7 before hitting a number other than 2,3,11 or 12. This is not the intuitively expected number of 1/6. It is a bit more frequent.
Odds Of Rolling A 7 In Craps
As I recall all the times I have spent at the craps tables, it does not seem to me that 1 out of every 4 times a point is set, that the shooter rolls a 7 right away.
1/5 is more often than 1/6, but it is not 1/4.
It's early, your math mileage may vary,
--Dorothy
Dorothy,
Betting Any 7 In Craps
Thanks for providing that math. I felt it would be less than 1/6, but I didn't know how to get to that number through mathematics.
So my break even point is one 7 out out of every 4 decisions, and my expected losing rolls is 1 out of every 5. Seems like the math is in my favor here. I'm sure I am missing something though.